document.write( "Question 397638: the perimeter of a rectangle is 100 ft. if its width is four times the length, then what is the area? \n" ); document.write( "
Algebra.Com's Answer #281731 by richard1234(7193)\"\" \"About 
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If the length is L and the width is 4L, then\r
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\n" ); document.write( "\n" ); document.write( "2(L + 4L) = 100 --> L + 4L = 50 --> L = 10, 4L = 40\r
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\n" ); document.write( "\n" ); document.write( "The dimensions are 10 and 40, so the area is 400.
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