document.write( "Question 397581: how many different permutations are possible for 4 people waiting in line to get on an airplanes \n" ); document.write( "
Algebra.Com's Answer #281704 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are 4 ways to choose the first person. For each of those 4 ways, there are 3 ways to choose the second person. So altogether, 4 times 3 times 2 times 1, or simply: 4!\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\"The

\n" ); document.write( " \n" ); document.write( "
\n" );