document.write( "Question 397360: If the line \r
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document.write( "y=A+B(x-3)
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document.write( "y=2x
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document.write( " and
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document.write( "it contains the point \r
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document.write( "(5,15)
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document.write( ", what are the values of \r
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document.write( "A and B?\r
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Algebra.Com's Answer #281656 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If the line \n" ); document.write( "y=A+B(x-3) \n" ); document.write( "is perpendicular to the line \n" ); document.write( "y=2x \n" ); document.write( "and \n" ); document.write( "it contains the point \n" ); document.write( "(5,15) \n" ); document.write( ", what are the values of \n" ); document.write( "A and B? \r \n" ); document.write( "\n" ); document.write( "y=A+B(x-3) \n" ); document.write( "This equation is a straight line of the standard form, y=mx+b, with m being the slope and b the y-intercept. \n" ); document.write( "In the given equation, B is the slope and A, the y-intercept. \n" ); document.write( "This line is perpendicular to another line, y=2x, whose slope=2. \n" ); document.write( "The negative reciprocal of this slope is the slope of the given line which would be -1/2 which is also equal to B \n" ); document.write( "The equation now reads y=-1/2(x-3)+A \n" ); document.write( "To find A, use the (x,y) coordinates given, and solve for A. \n" ); document.write( "15=-1/2(5-3)+A \n" ); document.write( "15=-1+A \n" ); document.write( "A=16 \n" ); document.write( "The equation now reads, y=(-1/2)(x-3)+16 \r \n" ); document.write( "\n" ); document.write( "Ans: \n" ); document.write( "B=-1/2 \n" ); document.write( "A=16 \n" ); document.write( " |