document.write( "Question 397193: train travelling @ 40kph leaves 10 mins before train travelling @ 60kph.when will they meet?? \n" ); document.write( "

Algebra.Com's Answer #281550 by josmiceli(19441) $\"\"$ $\"About$

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How far does the 1st train get in 10 min?
\n" ); document.write( " $\"d%5B1%5D+=+40%2A%281%2F6%29\"$ (10 min is 1/6 of an hour)
\n" ); document.write( " $\"d%5B1%5D+=+20%2F3\"$ km
\n" ); document.write( "Now if the 2nd train has to travel $\"d\"$ km to
\n" ); document.write( "meet the 1st train, then the 1st train has to
\n" ); document.write( "travel $\"d+-+20%2F3\"$ km
\n" ); document.write( "They will both travel for the same time period
\n" ); document.write( "1st train:
\n" ); document.write( "(1) $\"d+-+20%2F3+=+40t\"$
\n" ); document.write( "2nd train:
\n" ); document.write( "(2) $\"d+=+60t\"$
\n" ); document.write( "Substitute (2) in (1)
\n" ); document.write( " $\"60t+-+20%2F3+=+40t\"$
\n" ); document.write( " $\"180t+-+20+=+120t\"$
\n" ); document.write( " $\"60t+=+20\"$
\n" ); document.write( " $\"t+=+1%2F3\"$ hr
\n" ); document.write( "They will meet 20 min after the 2nd train leaves
\n" ); document.write( "check answer:
\n" ); document.write( "(2) $\"d+=+60t\"$
\n" ); document.write( " $\"d+=+60%2A%281%2F3%29\"$
\n" ); document.write( " $\"d+=+20\"$ km
\n" ); document.write( "and
\n" ); document.write( "(1) $\"d+-+20%2F3+=+40t\"$
\n" ); document.write( " $\"20+-+20%2F3+=+40%2A%281%2F3%29\"$
\n" ); document.write( " $\"60+-+20+=+120%2A%281%2F3%29\"$
\n" ); document.write( " $\"40+=+40\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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