document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=397152>Question 397152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you evaluate the logarithm 3 log(base2)of2 - log(base2)of4? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281543 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do you evaluate the logarithm 3 log(base2)of2 - log(base2)of4?\r<BR>\n" );
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document.write( "3 log(base2)of2 - log(base2)of4<BR>\n" );
document.write( "log2(2^3)-log2(4) (power rule)<BR>\n" );
document.write( "log2(2^3)/4 (division rule)<BR>\n" );
document.write( "log2(8/4)<BR>\n" );
document.write( "log2(2)=1 (The logarithm of its base is always equal to 1, that is, the base,2, must be raised to what number(logarithm=1) to equal 2.    <BR>\n" );
document.write( "           <BR>\n" );
document.write( "ans: (3 log(base2)of2 - log(base2)of4) = 1\r<BR>\n" );
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document.write( "check: 3log2(2)=3<BR>\n" );
document.write( "       log2(4)=log2(2^2)=2<BR>\n" );
document.write( "       3-2=1 </SPAN>\n" );
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