document.write( "Question 397089: The sum of 3 numbers is 49. The 2nd number is 5 minus 2 times the 1st number. The 3rd number is 6 minus the 1st number. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #281539 by Sarpi(32)\"\" \"About 
You can put this solution on YOUR website!
Solution
\n" ); document.write( "Let X1,X2 and X3 denote the three numbers.
\n" ); document.write( "=> X1= x
\n" ); document.write( " X2= 5-2*x \"5 minus 2 times the first number\"
\n" ); document.write( " X3= 6-x \"6 minus the first number\"
\n" ); document.write( "Therefore the sum of these three numbers should be equal to 49.
\n" ); document.write( "=> X1+X2+X3=49
\n" ); document.write( " x+(5-2x)+(6-x)=49
\n" ); document.write( " x+5-2x+6-x =49
\n" ); document.write( " x-2x-x =49-5-6
\n" ); document.write( " -2x=38
\n" ); document.write( " x =38/-2 which is -19.
\n" ); document.write( "So the first number is -19,
\n" ); document.write( "the second number is 5-2x
\n" ); document.write( " =5-2(-19)
\n" ); document.write( " =43
\n" ); document.write( "and the third number is 6-x
\n" ); document.write( " =6-(-19)
\n" ); document.write( " =6+19
\n" ); document.write( " =25
\n" ); document.write( "Thus by checking;
\n" ); document.write( "The sum of the three numbers is -19+43+25 which is indeed equal to 49. \n" ); document.write( "
\n" );