document.write( "Question 397057: Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?\r
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Algebra.Com's Answer #281497 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?
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\n" ); document.write( "Train A DATA:
\n" ); document.write( "rate = 80 mph ; time = x minutes ; distance = (x/60)(80) = (4/3)x miles
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\n" ); document.write( "Train B DATA:
\n" ); document.write( "rate = 88 miles; time = (x-15) minutes; distance = [(x-15)/60]88 miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "(4/3)x = (88/60)(x-15)
\n" ); document.write( "Multiply both sides by 60 to get
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\n" ); document.write( "80x = 88(x-15)
\n" ); document.write( "80x = 88x-88*15
\n" ); document.write( "8x = 88*15
\n" ); document.write( "x = 11*15
\n" ); document.write( "x = 161 minutes = 2 hrs 41 minutes
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\n" ); document.write( "6:25PM + 2hrs 41 minutes = 9:05 PM
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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