document.write( "Question 397057: Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?\r
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Algebra.Com's Answer #281490 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Train B passes the station at 6:40 PM. I know that train A
\n" ); document.write( "passed the station 15 min ago at 6:25 PM.
\n" ); document.write( "In 15 min, train A has travelled \"80%2A%281%2F4%29+=+20\" mi
\n" ); document.write( "Let \"d\" = distance train B has to go to catch train A.
\n" ); document.write( "Then \"d+-+20\" is the distance train A must go to
\n" ); document.write( "meet B.
\n" ); document.write( "For train A:
\n" ); document.write( "\"d+-+20+=+80t\"
\n" ); document.write( "For train B:
\n" ); document.write( "\"d+=+88t\"
\n" ); document.write( "Substitute \"d\" in 2nd equation into 1st equation
\n" ); document.write( "\"88t+-+20+=+80t\"
\n" ); document.write( "\"8t+=+20\"
\n" ); document.write( "\"t+=+5%2F2\" hr
\n" ); document.write( "train B will catch train A in 2.5 hrs after train B passed station.
\n" ); document.write( "6:40 PM + 2.5 = 9:10 PM
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