document.write( "Question 397057: Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?\r
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Algebra.Com's Answer #281484 by Edwin McCravy(20056) $\"\"$ $\"About$

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Train A and B are traveling in the same direction on parellel tracks. Train A is traveling 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 6:25 P.M. If train B passes the same station at 6:40 P.M., at what time will train B catch up to train A?\r
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document.write( "Some teachers do not like for you to use approach-rate when one thing is\r\n" );
document.write( "catching up to another, and separation rate when two things are going apart in\r\n" );
document.write( "opposite directions.  But I will, because it's often easier. In fact using\r\n" );
document.write( "approach rate, you can do this one in your head.\r\n" );
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document.write( "approach rate = the difference of the speeds\r\n" );
document.write( "separation rate = sum of the speeds\r\n" );
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document.write( "This problem uses approach rate of 88-80 = 8 mph.  Here goes:\r\n" );
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document.write( "During the  hour (15 minutes) between 6:25PM and 6:40PM, train A has gone\r\n" );
document.write( " of 80 miles or 20 miles from the station.  So A has a 20 mile head start on\r\n" );
document.write( "B at the time B leaves the station. Then B's approach rate is 88-80 or 8 miles\r\n" );
document.write( "per hour.  Since time = distance/rate, it will take B  or  or  hours,  So \r\n" );
document.write( "2 and a half hours from 6:40PM will be 9:10PM.\r\n" );
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document.write( "Edwin

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