document.write( "Question 397052: solve the linear system: x-2y=-5 , -3x+y=0 I need step by step help. \n" ); document.write( "
Algebra.Com's Answer #281476 by josmiceli(19441)\"\" \"About 
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Hi,\r
\n" ); document.write( "\n" ); document.write( "(1) \"x+-+2y+=+-5\"
\n" ); document.write( "(2) \"-3x+%2B+y+=+0\"
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\n" ); document.write( "The most important rule is:
\n" ); document.write( "\"What ever you do to one side of an equation,
\n" ); document.write( "you must do to the other side.\"
\n" ); document.write( "Multiply both sides of (2) by \"2\"
\n" ); document.write( "then add the equations
\n" ); document.write( "(1) \"x+-+2y+=+-5\"
\n" ); document.write( "(2) \"-6x+%2B+2y+=+0\" (notice that \"2%2A0+=+0\")
\n" ); document.write( "\"-5x+=+-5\"
\n" ); document.write( "\"x+=+1\"
\n" ); document.write( "Now substitute this value in (1)
\n" ); document.write( "(1) \"1+-2y+=+-5\"
\n" ); document.write( "Subtract \"1\" from both sides
\n" ); document.write( "\"-2y+=+-5+-+1\"
\n" ); document.write( "\"-2y+=+-6\"
\n" ); document.write( "Divide both sides by \"-2\"
\n" ); document.write( "\"y+=+3\"
\n" ); document.write( "The solution is (1,3)\r
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