document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=397052>Question 397052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the linear system: x-2y=-5 , -3x+y=0 I need step by step help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281469 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the linear system: x-2y=-5 , -3x+y=0<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "x-2y = -5<BR>\n" );
document.write( "-3x+y = 0<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Multiply thru the 1st equation by 3 to get:<BR>\n" );
document.write( "3x-6y = -15<BR>\n" );
document.write( "-3x+y = 0<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Add and solve for \"y\":<BR>\n" );
document.write( "-5y = -15<BR>\n" );
document.write( "y = 3<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Solve for \"x\":<BR>\n" );
document.write( "x-2y = -5<BR>\n" );
document.write( "x-2(3) = -5<BR>\n" );
document.write( "x-6 = -5<BR>\n" );
document.write( "x = 1<BR>\n" );
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document.write( "Solution: (1,3)<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================ </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );