document.write( "Question 397031: I'm stuck on a question, please help!! :)\r
\n" ); document.write( "\n" ); document.write( "\" Determine the equation of a circle with a diameter whose endpoints are P(5,-6) and Q(1,2)\" \r
\n" ); document.write( "\n" ); document.write( "I used the midpoint formula and got (3,-2) for the midpoint, and then sketched out the graph and ended up with 8 for the hypotenuse and 4 for the other side. So then I went
\n" ); document.write( "\"PQ=4^2+8^2=16 =16+64=80 \"
\n" ); document.write( "and then went
\n" ); document.write( "\" PQ = sqrt ( 80 ) \" \r
\n" ); document.write( "\n" ); document.write( "And now I'm stuck! How do I finish the question? And am I even doing this right??
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Algebra.Com's Answer #281464 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You find the midpoint, which is the center of the circle. Since you found the midpoint to be (3,-2), this means that the center of the circle is (3,-2). This is only possible because the line segment PQ is the diameter.\r
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\n" ); document.write( "\n" ); document.write( "Recall that the equation of the circle with radius 'r' and center (h,k) is \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So because the center of the circle is (3,-2), this means that \"h=3\" and \"k=-2\". Plug these values into the equation above to get \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2%2B%28y-%28-2%29%29%5E2=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "and simplify to get \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2%2B%28y%2B2%29%5E2=r%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So all we need to find out is the value of \"r%5E2\". So we need to find the value of the radius 'r'. It turns out that the distance from the center (3,-2) to either point will be equal to the radius (draw a picture if you're not sure)\r
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\n" ); document.write( "\n" ); document.write( "So to find 'r', let's find the distance from P(5,-6) to the center (3,-2)\r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=5\" and \"y%5B1%5D=-6\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=3\" and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29\" Start with the distance formula.\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%285-3%29%5E2%2B%28-6--2%29%5E2%29\" Plug in \"x%5B1%5D=5\", \"x%5B2%5D=3\", \"y%5B1%5D=-6\", and \"y%5B2%5D=-2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%282%29%5E2%2B%28-6--2%29%5E2%29\" Subtract \"3\" from \"5\" to get \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28%282%29%5E2%2B%28-4%29%5E2%29\" Subtract \"-2\" from \"-6\" to get \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%284%2B%28-4%29%5E2%29\" Square \"2\" to get \"4\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%284%2B16%29\" Square \"-4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"d=sqrt%2820%29\" Add \"4\" to \"16\" to get \"20\".\r
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\n" ); document.write( "\n" ); document.write( "So this distance is \"sqrt%2820%29\" units. So \"r=sqrt%2820%29\"\r
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\n" ); document.write( "\n" ); document.write( "This then means that \"r%5E2=%28sqrt%2820%29%29%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "So \"r%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "Plug this last value into the equation from the beginning to get \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2%2B%28y%2B2%29%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the circle with a diameter whose endpoints are P(5,-6) and Q(1,2) is \"%28x-3%29%5E2%2B%28y%2B2%29%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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