document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396810>Question 396810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve the following:\r<BR>\n" );
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document.write( "The three angles in a triangle always add up to 180 degrees.  If one angle in a triangle is 72 degrees and the second is 2 times the third, what are the angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281396 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The three angles in a triangle always add up to 180 degrees. If one angle in a triangle is 72 degrees and the second is 2 times the third, what are the angles?<BR>\n" );
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document.write( "Let the third be \"x\".<BR>\n" );
document.write( "Then the 2nd is \"2x\".<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 2x + 72 = 180<BR>\n" );
document.write( "3x = 108<BR>\n" );
document.write( "x = 36 degrees<BR>\n" );
document.write( "2x = 72 degree<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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