document.write( "Question 396802: How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
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Algebra.Com's Answer #281388 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution? \n" ); document.write( "---------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "1*x + 0.15*150 = 0.25(x+150) \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "100x + 15*150 = 25x + 25*150 \n" ); document.write( "75x = 10*150 \n" ); document.write( "---- \n" ); document.write( "x = 20 mL (amount pure acid needed for the mixture) \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |