document.write( "Question 396802: How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #281388 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How many milliliters of pure acid must be added to 150 milliliters of a 15% solution of acid to obtain a 25% solution?
\n" ); document.write( "----------
\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "1*x + 0.15*150 = 0.25(x+150)
\n" ); document.write( "-----
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "100x + 15*150 = 25x + 25*150
\n" ); document.write( "75x = 10*150
\n" ); document.write( "----
\n" ); document.write( "x = 20 mL (amount pure acid needed for the mixture)
\n" ); document.write( "=========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );