document.write( "Question 396756: this is the question i need answered:\r
\n" ); document.write( "\n" ); document.write( "-The isosceles trapezoid is part of an isosceles triangle with a 46\" degree vertex angle. What is the measure of an acute base angle of the trapezoid? Of an obtuse angle? The diagram is not to scale.\r
\n" ); document.write( "\n" ); document.write( "(then it shows a triangle with a midsegment and thats all.)\r
\n" ); document.write( "\n" ); document.write( "PLEASE HELP ME!
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Algebra.Com's Answer #281381 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Let's draw it to scale. Here's the trapezoid:\r
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\n" ); document.write( "\n" ); document.write( "and here is the rest of the isosceles triangle, of
\n" ); document.write( "which the isosceles trapezoid is a part:\r
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\n" ); document.write( "\n" ); document.write( "Next we draw the midsegment, which splits the figure in
\n" ); document.write( "half. It splits the 46° vertex angle into two 23° angles,\r
\n" ); document.write( "\n" ); document.write( "and the green line is perpendicular to both bases of
\n" ); document.write( "the trapezoid:\r
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\n" ); document.write( "\n" ); document.write( "Now we'll just look at the left half, which is a right triangle,
\n" ); document.write( "actually two right triangles:\r
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\n" ); document.write( "\n" ); document.write( "Since the two acute angles of a right triangle are complementary,
\n" ); document.write( "the other acute angle in both right triangles is \r
\n" ); document.write( "\n" ); document.write( "90°-23° or 67°:\r
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\n" ); document.write( "\n" ); document.write( "and the angle supplementary to the upper 67° angle is 180°-67° = 113°\r
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\n" ); document.write( "\n" ); document.write( "So therefore the original isosceles trapezoid has an acute
\n" ); document.write( "angle of 67° and an obtuse angle of 113°: \r
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