document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396704>Question 396704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The velocity of sound in air is given by the equation v=20&#8730;(273+t), where v is the velocity in meters per second and t is the temperature in degrees celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281352 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The velocity of sound in air is given by the equation v=20&#8730;(273+t), where v is the velocity in meters per second and t is the temperature in degrees celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree.<BR>\n" );
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document.write( "v=20&#8730;(273+t)<BR>\n" );
document.write( "329 = 20*sqrt(273+t)<BR>\n" );
document.write( "16.45 = sqrt(273+t)<BR>\n" );
document.write( "273+t = 16.45^2<BR>\n" );
document.write( "t- 16.45^2-273<BR>\n" );
document.write( "t = -2.4 degrees celsius<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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