document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43113>Question 43113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The approach pattern to an airport requires pilots to set an 11o angle of descent toward a runway. If a plane is flying at an altitude of 9,500 m, at what distance (measured along the ground) from the airport must the pilot decend  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28135 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you make a diagram, and construct a triangle, the 11° angle of descent equals the 11° in the triangle...we would use the tangent relationship...<BR>\n" );
document.write( "Let the distance we want to be x.<BR>\n" );
document.write( "Then tan 11° = 9500/x and<BR>\n" );
document.write( "x = 9500/tan 11°<BR>\n" );
document.write( "x = 48873 m or about 49000 meters (about 30 miles!) </SPAN>\n" );
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