document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42943>Question 42943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3a over 4a-20 + 9a over 6a-30\r<BR>\n" );
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document.write( "show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28132 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To combine these, we must convert each to their lowest common denominator...in this case that would be 12a-60...so we have\r<BR>\n" );
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document.write( "3a / (4a-20) + 9a / (6a-30) =<BR>\n" );
document.write( "9a / (12a-60) + 18a / (12a-60) =<BR>\n" );
document.write( "27a / (12a-60) now reduce to get<BR>\n" );
document.write( "27a / 12(a-5) =<BR>\n" );
document.write( "9a / 4(a-5) </SPAN>\n" );
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