document.write( "Question 5517: The product of two consecutive odd integers is 195.
\n" ); document.write( " i tried x(x+2)=195
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Algebra.Com's Answer #2813 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
You are right. \r
\n" ); document.write( "\n" ); document.write( "x(x+2) = 195\r
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\n" ); document.write( "\n" ); document.write( "It's quadratic, and it factors.
\n" ); document.write( "\"x%5E2+%2B+2x+-+195=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Basically you need two numbers whose product is 195 and whose difference is only 2, so the numbers will be numerically very close together. Try a number that is near the square root of 195. It would be somewhere between 13 and 15. In fact that is IT: 13 and 15!!\r
\n" ); document.write( "\n" ); document.write( "(x+15)(x-13)= 0\r
\n" ); document.write( "\n" ); document.write( "There are two solutions:
\n" ); document.write( "In the first case:
\n" ); document.write( "x= -15
\n" ); document.write( "x+2= -13\r
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\n" ); document.write( "\n" ); document.write( "In the second case:
\n" ); document.write( "x= 13
\n" ); document.write( "x+2 = 15.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \r
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