document.write( "Question 396592: The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the three numbers \n" ); document.write( "
Algebra.Com's Answer #281279 by mananth(16946)\"\" \"About 
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The sum of 3 integers is 123. The second number is two more than twice the first number. The third number is five less than the product of three and the first number. Find the three numbers
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\n" ); document.write( "let the integers be x, y, z
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\n" ); document.write( "x+y+z=123...........................1
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\n" ); document.write( "y=2x+2...............................2
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\n" ); document.write( "z=3x-5...............................3
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\n" ); document.write( "plug value of y & z in equation (1)
\n" ); document.write( "x+2x+2+3x-5 =123
\n" ); document.write( "6x-3=123
\n" ); document.write( "6x=126
\n" ); document.write( "/6
\n" ); document.write( "x= 21
\n" ); document.write( "y= 2x+2= 44
\n" ); document.write( "z=58\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "21+44+58=123
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\n" ); document.write( "m.ananth@hotmail.ca
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