document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396484>Question 396484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to solve this problem. I am sure that there is an equation to use but I do not know where to start. \r<BR>\n" );
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document.write( "A backyard pool is being drained. The pool contains 9925 gallons of water. At 9am, Drain 1 is opened which drains at 175 gallons every 15 minutes. At 10am, Drain2 is opened (Drain 1 continues draining, too) and it drains 450 gallons every 30 minutes. At what time will the pool contain 0 gallons of water? \r<BR>\n" );
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document.write( "THANK YOU! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281272 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A backyard pool is being drained. The pool contains 9925 gallons of water. At 9am, Drain 1 is opened which drains at 175 gallons every 15 minutes. At 10am, Drain2 is opened (Drain 1 continues draining, too) and it drains 450 gallons every 30 minutes. At what time will the pool contain 0 gallons of water? \r<BR>\n" );
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document.write( "THANK YOU!\r<BR>\n" );
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document.write( "let the total time to drain be x<BR>\n" );
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document.write( "Drain 1 = 700 gallons /h<BR>\n" );
document.write( "Drain 2 = 900 gallons/h<BR>\n" );
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document.write( "Drain 1 is open for x hours<BR>\n" );
document.write( "so it drained 700x gallons<BR>\n" );
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document.write( "Drain 2 is open for (x-1) hours<BR>\n" );
document.write( "so it drains 900(x-1) gallons<BR>\n" );
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document.write( "700x+900(x-1)=9925 <BR>\n" );
document.write( "700x+900x-900=9925<BR>\n" );
document.write( "1600x=9925+900<BR>\n" );
document.write( "1600x= 10825<BR>\n" );
document.write( "/2500<BR>\n" );
document.write( "x= 6.765 hours<BR>\n" );
document.write( "x= 6hours 46 minutes<BR>\n" );
document.write( "Time it will empty = 3.46 pm<BR>\n" );
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