document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396080>Question 396080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Newtons law of gravitation says that the force of gravitational attraction, F between two particles is directly proportional to the product of their masses, m1 and m2, and inversely proportional to the square of the distance, d, between them.\r<BR>\n" );
document.write( "\n" );
document.write( "I think the relationship is F=k(m1+m2)/d^2 Is this right? The next part of the question I need some help with please.\r<BR>\n" );
document.write( "\n" );
document.write( "If the two particles each lose half of their mass as the distance between them triples, how would the gravitational attraction between them change? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281260 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It should be\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f+=+k%28m%5B1%5D%2Am%5B2%5D%29%2Fd%5E2 ALIGN=MIDDLE  ALT=\"f+=+k%28m%5B1%5D%2Am%5B2%5D%29%2Fd%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > (the force is dependent on the product, not the sum). If m_1 and m_2 are each divided by 2, and the distance is tripled, then\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%5B2%5D+=+k%28%281%2F4%29m%5B1%5D%2Am%5B2%5D%29%2F%283d%29%5E2+=+%281%2F36%29f ALIGN=MIDDLE  ALT=\"f%5B2%5D+=+k%28%281%2F4%29m%5B1%5D%2Am%5B2%5D%29%2F%283d%29%5E2+=+%281%2F36%29f\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so the force caused by gravity is 1/36 as much.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "In case you're interested, the gravitational constant is approximately <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6.67%2A10%5E%28-11%29 ALIGN=MIDDLE  ALT=\"6.67%2A10%5E%28-11%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Nm^2/kg^2. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );