document.write( "Question 396387: Problem: The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers.
\n" ); document.write( "Here is what i have so far:
\n" ); document.write( "Let 1st number = x
\n" ); document.write( "2nd number = x+1
\n" ); document.write( "3rd number = x+2\r
\n" ); document.write( "\n" ); document.write( "3x+3 now I need to increase it by 10.
\n" ); document.write( "3x+3+10 re-written as 3x+13\r
\n" ); document.write( "\n" ); document.write( "3x+13= to the sum of the first two consecutive numbers.
\n" ); document.write( "which is 3x+13=x+x+1 re-written as 3x+13=2x+1\r
\n" ); document.write( "\n" ); document.write( "when I solved I got x=-12 is this correct? what am I doing wrong?? \n" ); document.write( "
Algebra.Com's Answer #281244 by ankor@dixie-net.com(22740)\"\" \"About 
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The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers.
\n" ); document.write( "Here is what i have so far:
\n" ); document.write( "Let 1st number = x
\n" ); document.write( "2nd number = x+1
\n" ); document.write( "3rd number = x+2
\n" ); document.write( "It says,\"The last of three consecutive numbers increased by ten \", that would be:
\n" ); document.write( "(x+2) + 10 = x+12
\n" ); document.write( "\"is equal to the sum of the first two consecutive numbers.\"
\n" ); document.write( "x + 12 = x + (x+1)
\n" ); document.write( "x + 12 = 2x + 1
\n" ); document.write( "12 - 1 = 2x - x
\n" ); document.write( "11 = x
\n" ); document.write( ":
\n" ); document.write( "11, 12, 13 are the numbers
\n" ); document.write( "Check it in the statement:
\n" ); document.write( "\"The last of three consecutive numbers increased by ten is equal to the sum of the first two consecutive numbers.\"
\n" ); document.write( "13 + 10 = 11 + 12 \n" ); document.write( "
\n" );