document.write( "Question 5513: I do not understand how the book came up with this answer
\n" ); document.write( "here is the two equations they are similar however they have different numbers.
\n" ); document.write( "#(1) 3/(2x+1)-1/x = 2x/x(2x+1)\r
\n" ); document.write( "\n" ); document.write( "this is what I am doing
\n" ); document.write( "I am multilplying each side by the lcd which is [x(2x+1)]. I understand that there is some canceling out that's why the rightside of the equation is 2x, but how did they get the ans. 3x-(2x+1) for the leftside of the equation. what happens to the 1/X? I can't see how this answer came to be. Please help me. :)
\n" ); document.write( "Mrs. Shavette Wiggins
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Algebra.Com's Answer #2812 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"3%2F%282x%2B1%29-1%2Fx+=+2x%2Fx%282x%2B1%29+\" I'm not sure exactly what you did, but this is the way it looked for me:\r
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\n" ); document.write( "\n" ); document.write( "It should look like this, when you multiply both sides by the LCD:
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\n" ); document.write( "\n" ); document.write( "Which boils down to this when you clear all the fractions:
\n" ); document.write( "\"3x+-+%282x%2B1%29+=+2x\"
\n" ); document.write( "\"3x+-+2x+-+1+=+2x+\"
\n" ); document.write( "\"x-1+=+2x\"
\n" ); document.write( "\"-1+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "Check to make sure none of the denoninators are zero, and it looks okay. It does check if you substitute x= -1 for x.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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