document.write( "Question 396287: 3(x+1)^(4/3)=48 \n" ); document.write( "
Algebra.Com's Answer #281148 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First let's isolate the base, (x+1), and its exponent, 4/3, on one side of the equation by dividing both sides by 3: \n" ); document.write( " \n" ); document.write( "Next we want to find a way to change the exponent from 4/3 to a 1. We can do so by combining all of the following ideas:
\n" ); document.write( "All of this tells us that if we raise each side of the equation to the reciprocal of 4/3 power, we will end up with an exponent of 1 on the left side. The reciprocal of 4/3 is 3/4: \n" ); document.write( " \n" ); document.write( "On the left side the exponent turns into a 1, as planned: \n" ); document.write( " \n" ); document.write( "Simplifying the left side is simple. The right side is not so simple. If you have trouble with negative or fractional exponents I find it can be helpful to factor the exponent in a certain way:
\n" ); document.write( "The exponent on the right is not negative but it is a fraction whose numerator is not a 1. So we will factor out the 3: \n" ); document.write( " \n" ); document.write( "Now, looking at the exponent in factored form, the 3 tells us we will be cubing and the 1/4 tells us that we will be finding a 4th root. And we can do these two operations in any order! Normally 4th roots aren't simple. However, since \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x+1 = 8 \n" ); document.write( "Now we just subtract 1: \n" ); document.write( "x = 7 \n" ); document.write( " |