document.write( "Question 396163: 81=27x \n" ); document.write( "
Algebra.Com's Answer #281101 by CharlesG2(834)\"\" \"About 
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81=27x\r
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\n" ); document.write( "\n" ); document.write( "if this is 81 = 27x, then 81/27 = x, simplified 3 = x
\n" ); document.write( "if this is 81 = 27^x and you want to know what the exponent x is:
\n" ); document.write( "logarithmic rule: if b^x = y, then logb y = x, where b is the base
\n" ); document.write( "log27 81 = x
\n" ); document.write( "logarithmic rule: logb x = (logk x)/(logk b)
\n" ); document.write( "logarithmic rule: when base omitted log is assumed to be log10
\n" ); document.write( "log27 81 = (log 81)/(log 27) = x
\n" ); document.write( "x = 1.333...
\n" ); document.write( "x = 4/3
\n" ); document.write( "27^(4/3) = 81\r
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