document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396161>Question 396161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A radiatior contains 6 liters of a 20% antifreeze solution. How much should be drained and replaced with pure antifeeze to produce a 50% antifreeze solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281098 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A radiatior contains 6 liters of a 20% antifreeze solution. How much should be drained and replaced with pure antifeeze to produce a 50% antifreeze solution?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = amount (liters) removed and replaced by pure antifreeze<BR>\n" );
document.write( "then<BR>\n" );
document.write( ".20(6-x) + x = .50(6)<BR>\n" );
document.write( "1.2-.2x + x = 3<BR>\n" );
document.write( "1.2 + .8x = 3<BR>\n" );
document.write( ".8x = 1.8<BR>\n" );
document.write( "x = 1.8/.8<BR>\n" );
document.write( "x = 2.25 liters\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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