document.write( "Question 396153: the cost of the item is $56 after a 20% discount....what is original price?
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Algebra.Com's Answer #281093 by jim_thompson5910(35256)\"\" \"About 
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Unfortunately the first answer is incorrect. Why? Because a 20% discount subtracts 20% of the original price from the original price. It's not simply 20% of the original price. This is a common pitfall with these types of problems.\r
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\n" ); document.write( "\n" ); document.write( "Let x = original price.\r
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\n" ); document.write( "\n" ); document.write( "Since \"the cost of the item is $56 after a 20% discount\", this means that \"x-0.2x=56\". Basically, the original price is x and 20% of this price is 0.2x. Subtract 0.2x from x to get the discount price of \"x-0.2x\" and set this equal to the known discount price of 56\r
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\n" ); document.write( "\n" ); document.write( "\"x-0.2x=56\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"0.8x=56\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"x=56%2F0.8\" Divide both sides by 0.8 to isolate x.\r
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\n" ); document.write( "\n" ); document.write( "\"x=70\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "So the original price is 70 dollars.\r
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\n" ); document.write( "\n" ); document.write( "Notice that 20% of 70 dollars is 0.2*70 = 14 dollars\r
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\n" ); document.write( "\n" ); document.write( "So subtract 14 dollars from 70 dollars to get: 70 - 14 = 56\r
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\n" ); document.write( "\n" ); document.write( "So this confirms our answer.
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