document.write( "Question 396125: what are the zeros of f(x)= 1/2x^2+5/2x-3/2
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Algebra.Com's Answer #281067 by checkley79(3341) $\"\"$ $\"About$

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f(x)= 1/2x^2+5/2x-3/2
\n" ); document.write( "f(x)=.5x^2+2.5x-1.5
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(-2.5+-sqrt[2.5^2-4*.5*-1.5))/2*.5
\n" ); document.write( "x=(-2.45+-sqrt[6.25+3])/1
\n" ); document.write( "x=(-2.5+-sqrt9.25)
\n" ); document.write( "x=(-2.5+-3.04)
\n" ); document.write( "x=-2.5+3.04
\n" ); document.write( "x=.54 ans.
\n" ); document.write( "x=-2.5-3.04
\n" ); document.write( "x=-5.46 ans.
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