document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396076>Question 396076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 29.  If you double the smaller number and the. Decrease it by the 10, the result is the larger number.  Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281049 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 29.  If you double the smaller number and the. Decrease it by the 10, the result is the larger number.  Find the numbers\r<BR>\n" );
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document.write( "let the smaller number be x<BR>\n" );
document.write( "the larger number be y<BR>\n" );
document.write( "x+y = 29..........................1<BR>\n" );
document.write( "2x-10=y<BR>\n" );
document.write( "2x-y=10...........................2<BR>\n" );
document.write( "add (1)& (2)<BR>\n" );
document.write( "3x =39<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=13 <BR>\n" );
document.write( "the other number = 39-13=16<BR>\n" );
document.write( "the numbers are 13 & 16<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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