document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=396048>Question 396048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> steve is three times as old as bubut. in 8 years, bubuts age will be one half that of steve's. what are their present ages? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #281041 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=281041\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> bubut = x years<BR>\n" );
document.write( "steve = 3x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "after 8 years<BR>\n" );
document.write( "bubut = x+ 8 years<BR>\n" );
document.write( "steve = 3x+8<BR>\n" );
document.write( "x+8 = 1/2(3x+8)<BR>\n" );
document.write( "2(x+8)=3x+8<BR>\n" );
document.write( "2x+16=3x+8<BR>\n" );
document.write( "3x-2x=16-8<BR>\n" );
document.write( "x= 8 bubut's age<BR>\n" );
document.write( "steve will be 3x = 24 years<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );