document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395915>Question 395915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dont know what this is and how to do it at all. Teacher does not explain at all.\r<BR>\n" );
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document.write( "y=2x-9<BR>\n" );
document.write( "x+3y=8\r<BR>\n" );
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document.write( "Solve each system by substitution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280950 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the expression for y from the first equation into the second equation to obtain a single-variable equation. As in,\r<BR>\n" );
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document.write( "x + 3(2x - 9) = 8\r<BR>\n" );
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document.write( "Then, you can easily solve for x, then plug in x into either equation to find y. </SPAN>\n" );
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