document.write( "Question 395841: Hi, I have a big test on complex numbers tomorrow and I am having a very hard time with this particular question:\r
\n" ); document.write( "\n" ); document.write( "Directions: On a complex plane, a point z has been graphed. your\r
\n" ); document.write( "\n" ); document.write( "If cosθ=(-8)/(22) and (π)/(2)≤θ≤π:\r
\n" ); document.write( "\n" ); document.write( "a) Find z in standard form.
\n" ); document.write( "b) Find z in trigonometric form. (Use whole degrees)\r
\n" ); document.write( "\n" ); document.write( "θ= Theta
\n" ); document.write( "π= pi
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Algebra.Com's Answer #280939 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"z\" is the unit vector that spins around the complex plane
\n" ); document.write( "with one end at the origin.
\n" ); document.write( "The information
\n" ); document.write( "(π)/(2)≤θ≤πis just telling you that
\n" ); document.write( "the unit vector is somewhere in the 2nd quadrant, past
\n" ); document.write( "90 degrees, but not beyond 180 degrees.
\n" ); document.write( "given:
\n" ); document.write( "\"cos%28theta%29+=+-8%2F22\"
\n" ); document.write( "I need to find
\n" ); document.write( "The amplitude of the vertical component is
\n" ); document.write( "\"sqrt%281+-+%288%2F22%29%5E2%29\"
\n" ); document.write( "\"sqrt%28%2822%5E2%2F22%5E2%29+-+%288%2F22%29%5E2%29\"
\n" ); document.write( "\"%281%2F22%29%2Asqrt%2822%5E2+-+8%5E2%29\"
\n" ); document.write( "\"%281%2F22%29%2Asqrt%28484+-+64%29\"
\n" ); document.write( "\"%281%2F22%29%2Asqrt%28420%29\"
\n" ); document.write( "\".9315\" is the imaginary amplitude
\n" ); document.write( "\"-8%2F22+=-+.3636\" real part
\n" ); document.write( "\"z\" in standard form is:
\n" ); document.write( "\"-.3636+%2B+.9315i\"
\n" ); document.write( "------------------
\n" ); document.write( "The angle whose cos = -.3636 is \"76.3\" degrees
\n" ); document.write( "\"180+-+76.3+=+103.69\" degrees
\n" ); document.write( "\"z\" at 104 degrees answer
\n" ); document.write( "Hopefully, I got it right\r
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