document.write( "Question 395581: One car leaves NY, traveling at an average speed of 65 mph and arrives in NJ. A second car travel the same route, but at 55 mph and takes an hour longer to get there. 1) How long did it take for each car to get to NJ and 2) how far is it away from NY? \n" ); document.write( "
Algebra.Com's Answer #280890 by ankor@dixie-net.com(22740)\"\" \"About 
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One car leaves NY, traveling at an average speed of 65 mph and arrives in NJ.
\n" ); document.write( " A second car travels the same route, but at 55 mph and takes an hour longer to get there.
\n" ); document.write( "1) How long did it take for each car to get to NJ?
\n" ); document.write( "Let t = time required by the faster car to get there
\n" ); document.write( "then
\n" ); document.write( "(t+1) = time required by the slower car
\n" ); document.write( ":
\n" ); document.write( "Both cars traveled the same distance, write a dist equation: dist = speed * time
\n" ); document.write( "65t = 55(t+1)
\n" ); document.write( "65t = 55t + 55
\n" ); document.write( "65t - 55t = 55
\n" ); document.write( "10t = 55
\n" ); document.write( "t = \"55%2F10\"
\n" ); document.write( "t = 5.5 hrs travel time of the faster car
\n" ); document.write( "then obviously, 6.5 hrs travel time of the slower
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( " 2) how far is it away from NY?
\n" ); document.write( "Find the dist using the faster car
\n" ); document.write( "65 * 5.5 = 357.5 mi
\n" ); document.write( "Check this distance using the slower car
\n" ); document.write( "55 * 6.5 = 357.5 mi
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