document.write( "Question 43064: 10 over t^7 times 3t^2 over 25t =\r
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Algebra.Com's Answer #28082 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
We can multiply and then cancel...or we can cancel first...
\n" ); document.write( "10 / t^7 * 3t^2 / 25t =
\n" ); document.write( "30t^2 / 25t^8 =
\n" ); document.write( "now 30/25 reduces to 6/5 and t^2 cancels, so we have
\n" ); document.write( "6 / 5t^6
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