document.write( "Question 395683: In a certain group of students, the probability that a student have experienced chickenpox is 0.7 and the probability of haven’t experienced it yet is 0.30. If 5 students are randomly selected with replacement, what is the probability that exactly one of them have experienced chickenpox? \n" ); document.write( "
Algebra.Com's Answer #280802 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = .7 q =.3
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"
\n" ); document.write( "P(1 of 5 have had chicken pox) = 5(.7)^1(.3)^4 = .0284 \n" ); document.write( "
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