document.write( "Question 395655: Please walk me thru this problem, especially how they got their factors:\r
\n" ); document.write( "\n" ); document.write( "Solve: 3x^2 + x - 2 = 0. They say that the factors are(3X-2)(X+1). Thank you.. \n" ); document.write( "
Algebra.Com's Answer #280789 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi, Previously posted
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document.write( "3x^2 + x - 2 = 0   |After factoring, the factors must represent the original
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document.write( "factoring to a product (__ ±  __)(  ±  __) Note: 2*-1 = -2 or -2*1 = -2
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document.write( " (3x ±  __)(x  ±  __)   |3x and x need to be in the 1st spots
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document.write( " (3x ±  __)(x  ±  __)   | 2 and 1 need to go into one or the other of 2nd spot blanks
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document.write( " (3x -2)(x+1)=0        |this arrangement works for the + and - using the 2 and 1
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document.write( " Noting: The SUM of the inner product(-2x) and the outer product(3x) = x\r
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document.write( "CHECKING our Answer
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document.write( " 3x(x+1) - 2(x+1) = 3x^2 + 3x - 2x - 2 = 3x^2 + x - 2\r
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document.write( " (3x -2)(x+1)=0    | x = 2/3 or x = -1
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