document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395469>Question 395469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELLO,<BR>\n" );
document.write( " I AM IN COLLEGE AGAIN AND HAVING THE WORST TIME FIGURING OUT STOPPING DISTANCE WORD PROBLEMS.The question is  The stopping distance of a car after the brakes are applied varies directly as the square of the speed r. If a car traveling 60 mph can stop in 200 feet, how many feet will it take the same car to stop when it is traveling 40 mph? The issue I am having is they want a fraction for an answer and I keep getting a non-fraction answer. I have tried to switch out the problem on the homework, but I CANT seem to get passed the second half. I would be very, sincerely helpful for any step by step , what the numbers mean, and where you got them guidance. The help on the assignment does not explain how the numbers are calculated or where they come from, and I have divided and multiplied and it is still a mystery.  <BR>\n" );
document.write( "Than you for the time and help,<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280752 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The stopping distance of a car after the brakes are applied varies directly as the square of the speed r. If a car traveling 60 mph can stop in 200 feet, how many feet will it take the same car to stop when it is traveling 40 mph? :<BR>\n" );
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document.write( "Use ratio, relationship of speed to stopping distance<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2%2Fs ALIGN=MIDDLE  ALT=\"r%5E2%2Fs\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ":<BR>\n" );
document.write( "let s = stopping distance at 40<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%5E2%2F200 ALIGN=MIDDLE  ALT=\"60%5E2%2F200\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40%5E2%2Fs ALIGN=MIDDLE  ALT=\"40%5E2%2Fs\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3600%2F200 ALIGN=MIDDLE  ALT=\"3600%2F200\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1600%2Fs ALIGN=MIDDLE  ALT=\"1600%2Fs\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "cross multiply<BR>\n" );
document.write( "3600s = 1600 * 200<BR>\n" );
document.write( "3600s = 32000<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=320000%2F3600 ALIGN=MIDDLE  ALT=\"320000%2F3600\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 88.89 ft to stop at 40 mph<BR>\n" );
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