document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395576>Question 395576</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi my name is Liz and I would like to know if you can help me solve this problem: a piece of wire that is 100 cm long is to be cut into two pieces, each to be bent to make a square. The lenght of a side of one square is to be twice the length of the other.  How should the wire be cut? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280714 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x  =edge of smaller square,<BR>\n" );
document.write( "2x  =edge of bigger square\r<BR>\n" );
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document.write( "Then the perimeter of the smaller square plus the perimeter of the bigger square must equal the length of the wire, or\r<BR>\n" );
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document.write( "4x + 4(2x) = 100 ==> 4x + 8x = 100 ==> 12x = 100 ==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+25%2F3+=+8%261%2F3 ALIGN=MIDDLE  ALT=\"x+=+25%2F3+=+8%261%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >cm. <BR>\n" );
document.write( "Therefore the wire should be cut 100/3 cm and 200/3 cm. </SPAN>\n" );
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