document.write( "Question 395544: Evaluate: \"int%28+sin%282011%282x-3%29pi%29%2A%282x-3%29%5E2011%2C+dx%2C+-1%2C4%29\" \n" ); document.write( "
Algebra.Com's Answer #280705 by richard1234(7193)\"\" \"About 
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Let \"u+=+2x+-+3\", \"du+=+2dx\". We now have\r
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\n" ); document.write( "\n" ); document.write( "\"int%28%28sin%282011u%2Api%29%2Au%5E2011%29%2C+du%29\" (I'm writing it at an indefinite integral for now. Don't forget the 1/2 at the end)\r
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\n" ); document.write( "\n" ); document.write( "Letting \"y+=+u%5E2011\", \"dz+=+sin+%282011u%2Api%29+du\", we obtain \"dy+=+2011u%5E2010du\" and \"z+=+%281%2F%282011%2Api%29%29%2A%28-cos+%282011u%2Api%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Applying integration by parts,\r
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\n" ); document.write( "\n" ); document.write( "Hopefully, by repeatedly using integration by parts, you should be able to get a sum of 2010 or 2011 terms that should be simplifiable in some way. However the easiest way is obviously to use the nint() function or the definite integral function on a graphing calculator.\r
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