document.write( "Question 395429: When the area of a rectangle is 3 times the length and the lenght is 1 more than twice the width, what are the demensions?\r
\n" ); document.write( "\n" ); document.write( "I know somthing is missing in my formula. Please help? Thanks.
\n" ); document.write( "A = L*W\r
\n" ); document.write( "\n" ); document.write( "W = x
\n" ); document.write( "L = 2x + 1\r
\n" ); document.write( "\n" ); document.write( "x(2x + 1) = 3(2x + 1)\r
\n" ); document.write( "\n" ); document.write( "2x^2 + x = 6x + 3\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 5x + 3\r
\n" ); document.write( "\n" ); document.write( "(2x + 3)(x+1) \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #280617 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
When the area of a rectangle is 3 times the length and the lenght is 1 more than twice the width, what are the demensions?\r
\n" ); document.write( "\n" ); document.write( "I know somthing is missing in my formula. Please help? Thanks.
\n" ); document.write( "A = L*W\r
\n" ); document.write( "\n" ); document.write( "W = x
\n" ); document.write( "L = 2x + 1\r
\n" ); document.write( "\n" ); document.write( "x(2x + 1) = 3(2x + 1)\r
\n" ); document.write( "\n" ); document.write( "2x^2 + x = 6x + 3
\n" ); document.write( "---
\n" ); document.write( "You missed the signs at this point:\r
\n" ); document.write( "\n" ); document.write( "2x^2 - 5x - 3 = 0\r
\n" ); document.write( "\n" ); document.write( "2x^2 -6x+x -3 = 0
\n" ); document.write( "---
\n" ); document.write( "2x(x-3)+(x-3) = 0
\n" ); document.write( "-----------------
\n" ); document.write( "(x-3)(2x+1) = 0
\n" ); document.write( "---
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 3 (width)
\n" ); document.write( "2x+1 = 7 (length)
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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