document.write( "Question 395429: When the area of a rectangle is 3 times the length and the lenght is 1 more than twice the width, what are the demensions?\r
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document.write( "I know somthing is missing in my formula. Please help? Thanks.
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document.write( "A = L*W\r
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document.write( "W = x
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document.write( "L = 2x + 1\r
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document.write( "x(2x + 1) = 3(2x + 1)\r
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document.write( "2x^2 + x = 6x + 3\r
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document.write( "2x^2 + 5x + 3\r
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document.write( "(2x + 3)(x+1) \r
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Algebra.Com's Answer #280617 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! When the area of a rectangle is 3 times the length and the lenght is 1 more than twice the width, what are the demensions?\r \n" ); document.write( "\n" ); document.write( "I know somthing is missing in my formula. Please help? Thanks. \n" ); document.write( "A = L*W\r \n" ); document.write( "\n" ); document.write( "W = x \n" ); document.write( "L = 2x + 1\r \n" ); document.write( "\n" ); document.write( "x(2x + 1) = 3(2x + 1)\r \n" ); document.write( "\n" ); document.write( "2x^2 + x = 6x + 3 \n" ); document.write( "--- \n" ); document.write( "You missed the signs at this point:\r \n" ); document.write( "\n" ); document.write( "2x^2 - 5x - 3 = 0\r \n" ); document.write( "\n" ); document.write( "2x^2 -6x+x -3 = 0 \n" ); document.write( "--- \n" ); document.write( "2x(x-3)+(x-3) = 0 \n" ); document.write( "----------------- \n" ); document.write( "(x-3)(2x+1) = 0 \n" ); document.write( "--- \n" ); document.write( "Positive solution: \n" ); document.write( "x = 3 (width) \n" ); document.write( "2x+1 = 7 (length) \n" ); document.write( "============= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |