document.write( "Question 43034: Factor Completly
\n" ); document.write( "2x^3 – 26x^2 + 80x\r
\n" ); document.write( "\n" ); document.write( "I am not quite sure how to factor this trinomial\r
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Algebra.Com's Answer #28061 by gsmani_iyer(201)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " \"2x%5E3-26%5E2%2B80x\"\r
\n" ); document.write( "\n" ); document.write( "= \"2x%28x%5E2-13x%2B40%29\"
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\n" ); document.write( "= \"2x%28x%5E2-5x-8x%2B40%29\"
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\n" ); document.write( "= \"2x%2A%28x%28x-5%29-8%28x-5%29%29\"
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\n" ); document.write( "= \"2x%2A%28x-5%29%2A%28x-8%29\" Answer. First of all factorise the expression by the common factor i.e. 2x. Then factorise x^2-13x+40 into (x-5)(x-8). As these factors cannot be further factorised, 2x*(x-5)(x-8) is the Answer. I hope this is clear to you. \r
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\n" ); document.write( "\n" ); document.write( "gsm
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