document.write( "Question 395344: the width of a box is 9 inches more than its length. the height of the box is 1 inch less than its length. if the box has a volume of 72 cubic inches, what are the dimensions of the box.\r
\n" ); document.write( "\n" ); document.write( "Height: x-1
\n" ); document.write( "Width: x+9
\n" ); document.write( "Length: x
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #280562 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "Letting x, (x-1)(x+9) represent the length, height and width respectively
\n" ); document.write( "Question states***
\n" ); document.write( " x(x-1)(x+9)= 72 in^3
\n" ); document.write( "solving for x
\n" ); document.write( " x^3 + 8x^2 - 9x - 72 = 0 |x = 3 is one solution found by substitution
\n" ); document.write( "(x-3)(x^2 + 11x + 24)= 0 |dividing (x^3 + 8x^2 - 9x - 72) by (x-3)
\n" ); document.write( "factoring the quadratic
\n" ); document.write( "(x-3)(x+3)(x+8) = 0 |tossing negative solutions out for length
\n" ); document.write( " x = 3
\n" ); document.write( "Dimensions of the box are 3in long, 2in high, 12in wide \n" ); document.write( "
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