document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395322>Question 395322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A long distance trucker traveled 80 miles in one direction during a snow storm. The return trip in rainy whether was accomplished at double the speed and took 2 hours less time. Find the speed going? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280549 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> remember the relationship distance=rate*time  or d=rt<BR>\n" );
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document.write( "going:   80 miles at speed r and time t   80=rt<BR>\n" );
document.write( "coming:  80 miles at speed 2r and time t-2  80=2r*(t-2) or 40=r(t-2)=rt-2r<BR>\n" );
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document.write( "80=rt and 40=rt-2r<BR>\n" );
document.write( "40=80-2r<BR>\n" );
document.write( "2r=40<BR>\n" );
document.write( "r=20 this is the going speed 20mph </SPAN>\n" );
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