document.write( "Question 395303: What is the equation of a circle with a diameter having endpoints at (3,2) and (9,10)? \n" ); document.write( "
Algebra.Com's Answer #280540 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( " D = \"sqrt+%28%28x1-x2%29%5E2%2B%28y1-y2%29%5E2%29%29\"
\n" ); document.write( "(9,10) and
\n" ); document.write( "(3,2) Diameter = \"sqrt+%28%286%29%5E2%2B%288%29%5E2%29%29\"= 10 |radius = 5
\n" ); document.write( "Midpoint ( \"%28x%5B1%5D+%2B+x%5B2%5D%29%2F2\", \"%28y%5B1%5D+%2B+y%5B2%5D%29%2F2\")
\n" ); document.write( " Midpoint Pt(6,6), the center of the circle
\n" ); document.write( "Standard Form of an Equation of a Circle is \"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"
\n" ); document.write( "where Pt(h,k) is the center and r is the radius
\n" ); document.write( "equation of a circle (x-6)^2 + (y-6)^2 = 25
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