document.write( "Question 395282: I couldn't find the proper place to submit this question, because you do not have a pre-calculus section on your website. Hopefully you can still answer this question.\r
\n" ); document.write( "\n" ); document.write( " (9x^2-24x-57)/(x+1)(x+3)(x-5) It's a partial fraction decomposition problem. I haven't done any of these in a while, so I can't remember what to do with (9x^2-24x-57).\r
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Algebra.Com's Answer #280539 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
set up the following equation
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\n" ); document.write( "next multiply both sides by the common denominator (x+1)(x+3)(x-5)
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\n" ); document.write( "\"%289x%5E2-24x-57%29=A%28x%2B3%29%28x-5%29%2BB%28x%2B1%29%28x-5%29%2BC%28x%2B1%29%28x%2B3%29\"
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\n" ); document.write( "at this point you can expand out all terms, then combined common terms and set correponding parts equal yielding a system of equation to solve for A,B and C
\n" ); document.write( "but another alternative is to select \"convenient values of x and solve
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\n" ); document.write( "x=-1: \"9%28-1%29%5E2-24%28-1%29-57=A%28-1%2B3%29%28-1-5%29%2BB%2A0%2BC%2A0\"
\n" ); document.write( "9+24-57=-12A or A=-24/-12=2
\n" ); document.write( "x=-3: \"9%28-3%29%5E2-24%28-3%29-57=A%2A0%2BB%2A%28-3%2B1%29%28-3-5%29%2BC%2A0\"
\n" ); document.write( "81+72-57=72B or B=96/72=4/3
\n" ); document.write( "x=5: \"9%285%29%5E2-24%285%29-57=A%2A0%2BB%2A0%2BC%2A%285%2B1%29%285%2B3%29\"
\n" ); document.write( "225-120-57=48C or C=48/48=1
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\n" ); document.write( "if I did my math correctly
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