document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395283>Question 395283</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hopefully you can answer this, I didn't seem to be able to locate a pre-calculus section on your website.<BR>\n" );
document.write( "The question is:\r<BR>\n" );
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document.write( "Find the 6 trig ratios for the angle whose terminal side contains the point (-2,5).  Then find the angle measure.\r<BR>\n" );
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document.write( "I'm basically clueless on this problem, so any help would be appreciated.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280531 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the point (-2,5) makes a right triangle whose hypotenus is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%285%5E2%2B%28-2%29%5E2%29=sqrt%2829%29 ALIGN=MIDDLE  ALT=\"sqrt%285%5E2%2B%28-2%29%5E2%29=sqrt%2829%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
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document.write( "the six trig ratios are;<BR>\n" );
document.write( "cos t = adjacent/hypotenus=-2/sqrt(29)<BR>\n" );
document.write( "sin t = opposite/hypotenus = 5/sqrt(29)<BR>\n" );
document.write( "tan t = opposite/adjacent= 5/-2<BR>\n" );
document.write( "cot t = adjacent/opposite = -2/5<BR>\n" );
document.write( "sec t = hypotenus/adjacent=sqrt(29)/2<BR>\n" );
document.write( "csc t = hypotenus /opposite = sqrt(29)/5<BR>\n" );
document.write( "The angle is using anyone of these and finding the arc value, for simplicity i'll use tan t=-2.5<BR>\n" );
document.write( "t=arc tan(-2.5)=180-arc tan(2.5)=180-68.2=111.8 </SPAN>\n" );
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