document.write( "Question 43001: Carla invested $28,000, part at 14% and part at 9%. If the total interest at the end of the year is $3,370, how much did she invest at 14%? \n" ); document.write( "
Algebra.Com's Answer #28053 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .14x+.09(28000-x)=3370 or .14x+2520-.09x=3370 or .05x=850 or x=850/.05 or\r \n" ); document.write( "\n" ); document.write( "x=17000 invested @ 14% & 28000-17000=11000 @ 9% \n" ); document.write( " \n" ); document.write( " |