document.write( "Question 395274: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
\n" ); document.write( " $\"f%28x%29=x%5E2-12x-5\"$
\n" ); document.write( "The vertex is ___.
\n" ); document.write( "(Type an ordered pair)
\n" ); document.write( "The equation for the line of symmetry is x=___.
\n" ); document.write( "The maximum/minimum of f(x) is ___.
\n" ); document.write( "Is the value, f(6)=-41 a minimum or a maximum?
\n" ); document.write( "Graph. \n" ); document.write( "

Algebra.Com's Answer #280527 by Earlsdon(6294) $\"\"$ $\"About$

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The x-coordinate of the vertex is given by:
\n" ); document.write( " $\"x+=+-b%2F2a\"$ and here, a = 1 and b = -12,
\n" ); document.write( " $\"x+=+-%28-12%29%2F2%281%29\"$
\n" ); document.write( " $\"x+=+6\"$ substitute into the given equation to find the y-coordinate of the vertex:
\n" ); document.write( " $\"y+=+x%5E2-12x-5\"$
\n" ); document.write( " $\"y+=+6%5E2-12%286%29-5\"$
\n" ); document.write( " $\"y+=+-41\"$
\n" ); document.write( "The vertex is at: (6, -41)
\n" ); document.write( "The equation of the line of symmetry is: x = 6
\n" ); document.write( "The vertex (6, -41) is a minimum because the parabola opens upwards (positive coefficient of $\"x%5E2\"$ ).
\n" ); document.write( " $\"graph%28400%2C400%2C-5%2C20%2C-45%2C5%2Cx%5E2-12x-5%29\"$
\n" ); document.write( " \n" ); document.write( "

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