document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=395269>Question 395269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs a 26% acid mixture, but his lab only has 20% and 35% solutions.  If he needs a total of 80 liters of the 26% solution, how much of each percent acid does he need?\r<BR>\n" );
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document.write( "I was thinking:<BR>\n" );
document.write( ".20(x) + .35(y) = .26(80) \r<BR>\n" );
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document.write( "but I'm stuck and it just doesnt' seem like the right way to do it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #280516 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=280516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist needs a 26% acid mixture, but his lab only has 20% and 35% solutions. If he needs a total of 80 liters of the 26% solution, how much of each percent acid does he need? <BR>\n" );
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document.write( "If you want to use 2 variables you made a good start.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "Quantity Equation: x + y = 80 liters<BR>\n" );
document.write( "Acid Equation::::0.20x+0.35y = 0.26*80<BR>\n" );
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document.write( "Multiply thru 1st by 20<BR>\n" );
document.write( "Multiply thru 2nd by 100<BR>\n" );
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document.write( "20x + 20y = 20*80<BR>\n" );
document.write( "20x + 35y = 26*80<BR>\n" );
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document.write( "Subtract 1st from 2nd and solve for \"y\":<BR>\n" );
document.write( "15y = 6*80<BR>\n" );
document.write( "y = 32 liters (amt. of 35% solution needed)<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x+y = 80<BR>\n" );
document.write( "x + 32 = 80<BR>\n" );
document.write( "x = 48 liters (amt. of 20% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========== </SPAN>\n" );
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